Each load will take 3 gallons. Therefore, we can express the amount of water that will be used for x loads using the equation w=3x, where w is how much water you use and x is equal to how many loads there are. We can set up the equation: w=(3*4)+(3*[tex] \frac{1}{9} [/tex]) From there, we can solve w=12+(3*[tex] \frac{1}{9} [/tex]) simplifies to w=12+[tex] \frac{1}{3} [/tex] w= 12[tex] \frac{1}{3} [/tex]
