Fred123
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When a certain metal is illuminated with light of frequency 3.1 ✕ 1015 Hz, a stopping potential of 6.6 V is required to stop the most energetic ejected electrons. What is the work function of this metal?

Answer= Ev

Respuesta :

The ejected electrons have a kinetic energy of 10 eV. 
The incoming photons have an energy 
E = h f = 3.008 10^(-18) J = 18.776 eV 
The work function is the difference between those two: 8.776 eV
The ejected electrons have a kinetic energy of 10 eV. 
The incoming photons have an energy 
E = h f = 3.008 10^(-18) J = 18.776 eV 
The work function is the difference between those two: 8.776 eV

hope it helps