Respuesta :
Answer: Mass of oxygen atom in given amount of compound is 30.88 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
Given mass of [tex]C_2H_2O_2=56g[/tex]
Molar mass of [tex]C_2H_2O_2=58g/mol[/tex]
Putting values in above equation, we get:
[tex]\text{Moles of }C_2H_2O_2=\frac{56g}{58g/mol}=0.965mol[/tex]
In 1 mole of [tex]C_2H_2O_2[/tex], 2 moles of carbon atoms, 2 moles of oxygen atoms and 2 moles of hydrogen atoms.
So, in 0.965 moles of [tex]C_2H_2O_2[/tex], moles of oxygen atoms will be = [tex]\frac{2}{1}\times 0.965=1.93mol[/tex]
Calculating the mass of oxygen atoms by using equation 1:
Moles of oxygen atoms = 1.93 moles
Molar mass of oxygen atom = 16 g/mol
Putting values in equation 1, we get:
[tex]1.93mol=\frac{\text{Mass of oxygen atom}}{16g/mol}\\\\\text{Mass of oxygen atom}=30.88g[/tex]
Hence, mass of oxygen atom in given amount of compound is 30.88 grams.
30.88 grams of oxygen is the mass present in [tex]\rm C_{2}H_{2}O_{2}[/tex].
The mass of the substance is the product of the number of moles and the molar mass of the substance of that compound. It is measured in grams.
How to calculate the mass of the oxygen?
Given,
- Mass (m) of [tex]\rm C_{2}H_{2}O_{2}[/tex] = 56 gm
- Molar mass (M) of [tex]\rm C_{2}H_{2}O_{2}[/tex] = [tex]58 \;\rm g \;mol^{-1}[/tex]
Moles can be calculated as,
[tex]\rm Moles (n) = \dfrac{\rm Mass}{\rm Molar\; mass}[/tex]
Substituting values in the equation as:
[tex]\begin{aligned}\rm Moles\; of \;C_{2}H_{2}O_{2} &= \dfrac{56 \;\rm g}{58\;\rm g\; mol^{-1}}\\\\&= 0.965\;\rm mol\end{aligned}[/tex]
In the compound [tex]\rm C_{2}H_{2}O_{2}[/tex]:
- Moles of carbon atom = 2
- Moles of hydrogen atom = 2
- Moles of oxygen atom = 2
So, the moles of oxygen in the compound will be:
[tex]\begin{aligned}&=\dfrac{2}{1}\times 0.965\\\\&= 1.93 \;\rm mol\end{aligned}[/tex]
Now calculate the mass of the oxygen as the above formula:
Moles (n) of oxygen atoms = 1.93 moles
Molar mass (M) of oxygen atom = [tex]16 \;\rm g\;mol^{-1}[/tex]
Substituting values in the equation,
[tex]\begin{aligned}1.93 \;\rm mol &= \dfrac{\text{Mass of oxygen}}{16 \;\rm g \;mol^{-1}}\\\\&= 30.88 \;\rm g \;mol^{-1}\end{aligned}[/tex]
Therefore, 30.88 gm of oxygen is present in [tex]\rm C_{2}H_{2}O_{2}[/tex].
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