The point slope form of a line is y-y2=m(x-x2), where m=slope an (x2,y2) is any point on the line.
First find the slope, m, which is:
m=(y2-y1)/(x2-x1), in this case:
m=(2--4)/(0--3)
m=(2+4)/(0+3)
m=6/3
m=2 so now we have:
y-y2=2(x-x2), using either point finishes the line, I'll use (-3,-4)...
y+4=2(x+3)
