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A four digit number has digit form 'a4b2' If it is divisible by 3, what are the possible values of a+b?

Respuesta :

Adithya027

Answer:

3,6,9

Step-by-step explanation:

If any number is divisible by 3, then it's sum should be divisible by 3

So, in a4b2, a+b+4+2 should be divisible by 3

Hence a+b+6 should be divisible by 3

Hence a+b should be divisible by 3 as 6 is already divisible by 3

Hence a+b can be 3,6,9 [It can go above that as a and b are single digit numbers]

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