Respuesta :

irspow
I will assume that everything after the radical sign is under the sign...

6√(64x^4y^2)

6√(8^2(x^2)^2(y^2))  removing all of the perfect squares...

6*8*x^2*y

48x^2y
Banabanana
[tex]6 \sqrt{64x^4y^2}=6 \sqrt{8^2} \sqrt{(x^2)^2} \sqrt{y^2} =6*8x^2y=48x^2y [/tex]

Edited:
[tex] \sqrt[6]{64x^4y^2}= \sqrt[6]{2^6x^4y^2}= 2 \sqrt[6]{x^4y^2} [/tex]