The radius of the ball is 13 units.
Its volume is
V₁ = (4π*13³)/3
= 9.2028 x 10³ units³
The drilled hole has the approximate shape of a solid cylinder with radius = 6 and length = 26. Its volume is
V₂ = π*(6²)*26
= 2.9405 x 10³ units³
The volume of the resulting solid is
V₁ - V₂ = 6.2622 x 10³
Answer: 6.2622 x 10³ units³
