contestada

It takes 3.3 j of work to stretch a hooke's-law spring 15 cm from its unstressed length. how much the extra work is required to stretch it an additional 11.3 cm? answer in units of j.

Respuesta :

5.786j

Set up a proportion. Add 11.3 and 15=26.3cm.
Next, the proportion of 3.3j/15cm=×/26.3cm