Write the point-slope form of the equation for a line that passes through (6, –1) with a slope of 2. The value of x1 is . The value of y1 is . The point-slope form of the equation is .

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Answer:

The value of x1 is:6

The value of y1 is:-1

The point-slope form of the equation is:

y – 1 = 2(x + 6)

y + 1 = 2(x – 6)✔

1 – y = 2(6 + x)

1 + y = 2(6 – x).

From the equation for a line that passes through (6, –1) with a slope of 2.

The value of x1 is 6

The value of y1 is -1

Point - slope form of the equation is

[tex]y+1=2(x-6)[/tex]

Given :

a line that passes through (6, –1) with a slope of 2.

To write point slope form of equation of line we use point - slope formula

[tex]y-y_1=m(x-x_1)[/tex]

where m is the slope

(x1,y1) is the given point

Given point is (6,-1).

The value of x1 is 6

The value of y1 is -1

Given slope m=2. Replace all the values inside the formula

[tex]y-y_1=m(x-x_1)\\y-(-1)=2(x-6)\\\\y+1=2(x-6)[/tex]

Point - slope form of the equation is

[tex]y+1=2(x-6)[/tex]

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