Respuesta :
Answer:
64a+24b+16c = 24
Step-by-step explanation:
Given : 8a + 3b + 2c = 3
We have to find the value of 64a+24b+16c
Consider 64a+24b+16c
Taking 8 common from each term , we have,
64a+24b+16c = 8(8a + 3b + 2c)
Also, given 8a + 3b + 2c = 3
Then , 64a+24b+16c = 8(8a + 3b + 2c)
= 8(3)
Simplify , we have,
= 24
Thus, 64a+24b+16c = 24