Respuesta :
You first us 1/2(mv^2) to solve for the potential energy and then put that in to PE=m*g*h and solve for hight
Answer : Maximum height of the pendulum is 0.43 m
Explanation :
Given that,
Mass of the pendulum, m = 2 kg
Speed of the pendulum, v = 2.9 m/s
When it reaches the lowest point on its path, the potential energy at the highest point is equal to the kinetic energy at the lowest point.
i.e.
[tex]KE=PE[/tex]
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
h is the height of the pendulum.
[tex]h=\dfrac{v^2}{2g}[/tex]
[tex]h=\dfrac{(2.9\ m/s)^2}{2\times 9.8\ m/s^2}[/tex]
[tex]h=0.43\ m[/tex]
Hence, this is the required solution.