contestada

In a rectangular coordinate system a positive point charge q=6.00⋅ 10 −9 C is placed at the point x = +0.150 m , y = 0, and an identical point charge is placed at x = -0.150 m , y = 0.

Respuesta :

W0lf93
I'm guessing that the question is how much force is pulling the two charges together. I'll use Coulomb's law where Force = k*Q1*Q2/r^2, where k is Coulomb's Constant= 8.99*10^9. First, r = distance between points = sqrt((0.150+0.15)^2+0^2) = 0.3 Entering this info into the equation = (8.99*10^9)*(6*10^-9)*(6*10^-9)/(0.3)^2 = 3.60*10^-6 Newtons away from each other They repel since both are positive).

Otras preguntas