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The following observed values of x and y are thought to satisfy a linear equation. Write the linear equation.

Draw the graphs using the values of x ,y as given in the above table.
At what points the graph of the linear equation (i) cuts the x-axis (ii) cuts the y-axis.

The following observed values of x and y are thought to satisfy a linear equation Write the linear equation Draw the graphs using the values of x y as given in class=

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lesliekolleroxrkcf
slope=(-2-6)/(6--6)=-8/12=-2/3
use point slope formula
y+2=-2/3(x-6)
y=-2/3x + 2. in slope intercept

I) cuts x axis at (-4/3,0)
I) cuts y axis at (0,2)

Answer:

Step-by-step explanation:

Given are two points on a straight line.

(since x and y are thought to satisfy a linear equation. )

The two points are (x,y) = (6,-2) (-6,6)

Use the two point formula for finding equation

Two point formula is

[tex]\frac{y-y_1}{y_2-y_1}= \frac{x-x_1}{x_2-x_1}[/tex]

Substitue the values to get

[tex]\frac{x-(-6)}{6-(-6)} =\frac{y-6}{-2-6} \\x+6 =\frac{12}{-8}(y-6) \\-2x-12=3y-18\\2x+3y=6[/tex]

is the equation

This can also be written in intercept form as

[tex]\frac{x}{3} +\frac{y}{2} =1[/tex]

Hence x intercept = 3 and y intercept = 2

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