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A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement? (Use trigonometry to solve.)

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Chlidonias

Answer:

X = 192.5 m Y = 134.8 m

Explanation:

Horizontal Displacement

X = 235cos35

X = 192.5 m

Vertical Displacement

Y = 235sin35

Y = 134.8 m

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