Respuesta :
Answer is: the coefficient of phosphoric acid is 12.
Chemical reaction: P₄S₃ + NO₃⁻ + H⁺ → H₃PO₄ + SO₄⁻ + NO.
Reduction half reaction: NO₃⁻ + 4H⁺ + 3e⁻ → NO + 2H₂O /·38
Oxidation half reaction: P₄S₃ + 28H₂O → 4H₃PO₄ + 3SO₄²⁻ + 44H⁺ + 38e⁻ /·3.
38NO₃⁻ + 152H⁺ + 3P₄S₃ + 84H₂O → 38NO + 76H₂O + 12H₃PO₄ + 9SO₄²⁻ + 132H⁺.
Balnced chemical reaction:
3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO.
Chemical reaction: P₄S₃ + NO₃⁻ + H⁺ → H₃PO₄ + SO₄⁻ + NO.
Reduction half reaction: NO₃⁻ + 4H⁺ + 3e⁻ → NO + 2H₂O /·38
Oxidation half reaction: P₄S₃ + 28H₂O → 4H₃PO₄ + 3SO₄²⁻ + 44H⁺ + 38e⁻ /·3.
38NO₃⁻ + 152H⁺ + 3P₄S₃ + 84H₂O → 38NO + 76H₂O + 12H₃PO₄ + 9SO₄²⁻ + 132H⁺.
Balnced chemical reaction:
3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO.
The answer correct answer is 12.
The coefficient of H3PO4 is 12. The balanced chemical equation for the reaction is; 3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO; The reaction is a redox reaction; where some elements undergo oxidation (loss of electrons) while the other undergo reduction (gaining of electrons). The half reaction for the reduction is; NO3- + 4H+ + 3e---> NO + 2H2O, while the oxidation half reaction is; P4S3 + 28 H2O --> H3PO4 + 3SO42- + 4H+ + 38 e-; To obtain a complete and balanced equation; we then multiply by the coefficients such that the electrons on both sides cancel and add the half reactions together. which eventually gives us; 3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO
The coefficient of H3PO4 is 12. The balanced chemical equation for the reaction is; 3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO; The reaction is a redox reaction; where some elements undergo oxidation (loss of electrons) while the other undergo reduction (gaining of electrons). The half reaction for the reduction is; NO3- + 4H+ + 3e---> NO + 2H2O, while the oxidation half reaction is; P4S3 + 28 H2O --> H3PO4 + 3SO42- + 4H+ + 38 e-; To obtain a complete and balanced equation; we then multiply by the coefficients such that the electrons on both sides cancel and add the half reactions together. which eventually gives us; 3P₄S₃ + 38NO₃⁻ + 20H⁺ + 8H₂O → 12H₃PO₄ + 9SO₄²⁻ + 38NO