These are three questions and three answers
1. Question 1.
Part
1:
Answer: 5 N*s
Explanation:
Data:
F = 125 N
m = 141 g = 0.141 kg
t = 0.04 s
Δp =?
2) Formula
Impulse = F.t =
Impulse = Δp
3) Solution:
=> Δp => F.t
Δp = 125 N * 0.04 s = 5 N.m
2) Question 2
Part 2: If the initial speed of the baseball is v = 0.0 m/s, what will its speed be when it leaves the pitcher's hand?
Answer: 35.5 m/s positive (toward the homelate)
Explanation:
1) Data:
vi = 0.0 m/s
vf = ?
2) Formula
Δp = mΔv
3) Solution:
Δv = Δp / m
Δv = 5 N*s / 0.141 kg = 35.5 m/s
Δv = vf - vi => vf = Δv + vi = 35.5 m/s + 0 = 35.5 m/s, positive because it is toward the homeplate.
3) Question 3
Part 3: When the batter hits the ball, a net force of 1165 N, opposite
to the direction of the ball's initial motion, acts on the ball for
0.005 s during the hit. What is the final velocity of the ball?
Answer: - 76.8 m/s (negative because it is towards the field)
Explanation:
1) Data:
F = 1165 N
t = 0.005 s
vf = ?
2) Formulas
I = f.t
I = Δp
Δp = mΔv
3) Solution
I = F.t = 1165 N * 0.005s = 5,825 N*s
Δp = I = 5,825 N*s
Δp = mΔv => Δv = Δp / m = 5,825 N*s / 0.141 kg = 41.3 m/s (negative because it is towards the field)
Δv = vf - vi => vf = Δv + vi = - 41.3 m/s - 35.5 m/s = - 76.8 m/s
