There is no attached picture, but I guess it is like the one I attached. If so, the first thing is finding the side measure: [tex]A_{square}=l^2 \\ l= \sqrt{A} = \sqrt{900} \;\;\Rightarrow l=30\;in[/tex] Now, radius is half this measure: 15 in. And circle area is: [tex]A_{circle}=\pi r^2=\pi\cdot(15)^2\:\;\Rightarrow A_{circle}=225\pi\;in^2[/tex]
