colleenorellanp6y2t5 colleenorellanp6y2t5
  • 10-04-2018
  • Mathematics
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What are the roots of the polynomial equation? x2−12x−64=0

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Аноним Аноним
  • 10-04-2018

[tex] {x}^{2} - 12x - 64 = 0 \\ (x - 16)(x + 4) = 0[/tex]
x = 16, x = -4

Hope this helps. - M
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