Respuesta :

MarkV
Hi there!

A. Plug in -5 for the variable x.
[tex]f( - 5) = 3 - 2 \times - 5 = 3 + 10 = 13[/tex]

B. Plug in 0 for the variable x.
[tex]f(0) = 3 - 2 \times 0 = 3 - 0 = 3[/tex]

C. Plug in 2 for the variable x.
[tex]f(2) = 3 - 2 \times 2 = 3 - 4 = - 1[/tex]
A= 13
B=3
C= -1

this is correct^^^