We have the following functions: f (x) = 3x + 1 g (x) = x ^ 2-6 We must add both functions. We have then: (f + g) (x) = f (x) + g (x) Substituting we have: (f + g) (x) = (3x + 1) + (x ^ 2-6) Then, rewriting: (f + g) (x) = x ^ 2 + 3x - 5 Answer: (f + g) (x) = x ^ 2 + 3x - 5
