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The relative locations of Marilyn's house, Bobby's house, and Kimberly's house are shown in the figure.


What is the distance from Kimberly's house to Marilyn's house?



Enter your answer in the box. Round your final answer to the nearest whole number.

The relative locations of Marilyns house Bobbys house and Kimberlys house are shown in the figure What is the distance from Kimberlys house to Marilyns house En class=

Respuesta :

Using sine rule :

[tex] \dfrac{a}{sin A} = \dfrac{b}{sin B} [/tex]

[tex] \dfrac{14}{sin(63)} = \dfrac{b}{sin(50)} [/tex]

[tex]bsin(63) = 14sin(50)[/tex]

[tex]b = \dfrac{14sin(50)}{sin(63) }[/tex]

[tex]b = 12.04 \ mi \text{(nearest hundredth)}[/tex]

Answer: The distance is 12.04 miles

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