Find the kinetic energy K of a particle of mass m, moving in a circular path, if L is its angular momentum and I is its moment of inertia about the center of the circle. Express your answer in terms of the variables L and I.

Respuesta :

Answer:

k=[tex]\frac{1}{2}L^2/I[/tex]

Explanation:

we know that:

L = IW

where L is the angular momentum, I the moment of inertia and W is the angular velocity.

and Also we know that:

k=[tex]\frac{1}{2}IW^2[/tex]

Now, we solve the first equation for W and get:

W = L/I

Replacing W on the first equation we get:

[tex]k=\frac{1}{2}I(\frac{L}{I})^{2} =\frac{1}{2} \frac{L^{2}}{I}[/tex]