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10-12-2015
Mathematics

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a+b+c=18,b+c=10,c-b=6

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redcloud redcloud

10-12-2015

c-b=6
solve for c
c=b+6
substitute b+6 for c
b+c=10
b+(b+6)=10
2b=4
b=2
substitute that in to find C
c-b=6
c-2=6
c=8
a+b+c=18
a+2+8=18
a+10=18
a=8

so a=8, b=2, c=8

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